=>|(x+2)(x-3)|=x+2
\(\Leftrightarrow\left\{{}\begin{matrix}x>=-2\\\left[\left(x+2\right)\left(x-3\right)\right]^2-\left(x+2\right)^2=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x>=-2\\\left(x+2\right)^2\cdot\left(x-4\right)\left(x-2\right)=0\end{matrix}\right.\Leftrightarrow x\in\left\{-2;4;2\right\}\)