Question

x\(^2\) - 2017x+2016

Answer 1

\(x^2-2017x+2016=x^2-x-2016x+2016=\left(x^2-x\right)-\left(2016x+2016\right)\)

\(=x.\left(x+1\right)+2016.\left(x+1\right)=\left(x+2016\right)\left(x+1\right)\)

Vậy...

Answer 2

\(x^2-2017x+2016=x^2-2016x-x+2016\)

\(=\left(x^2-2016x\right)-\left(x-2016\right)\)

\(=x.\left(x-2016\right)-\left(x-2016\right)\)

\(=\left(x-2016\right).\left(x-1\right)\)

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