Question

(x^2-1)(x+3)=0

Answer 1

`(x^2-1)(x+3) =0`

`<=> (x-1)(x+1)(x+3) = 0`

`<=>` \(\left[{}\begin{matrix}x-1=0\\x+1=0\\x+3=0\end{matrix}\right.\)

`<=>` \(\left[{}\begin{matrix}x=1\\x=-1\\x=-3\end{matrix}\right.\)

Answer 2

=>(x-1)(x+1)(x+3)=0

hay \(x\in\left\{1;-1;-3\right\}\)