tim x\(\in\)N biet
107.10x+3=217.517
x2017=x
tim x
\(5^{x-1}-1=0\)
\(5^{x-1}< 1000\) tim x
\(27^{x-1}=9^2\) tim x
giup mk
tim x
\(2\cdot3^x=10\cdot3^{12}+8\cdot27^4\)
mk dang can gap giup mk nhe
tim x
2X =32
9x-1=9
(x-2)^3-27^2=0
tim x
Tìm x
a) x10 = 1x
b) x10 = x
c) ( 2x - 15 )5 = ( 2x - 15 )3