\(2.3^x=10.3^{12}+8.27^4\)
\(\Rightarrow\)\(2.3^x=10.3^{12}+2^3.3^{12}\)
\(\Rightarrow\)\(2.3^x=3^{12}\left(10+8\right)\)
\(\Rightarrow\)\(2.3^x=3^{12}.18=3^{12}.2.3.3=3^{14}.2\)
Vậy x = 14
\(2.3^x=10.3^{12}+8.27^4\)
\(\Rightarrow\)\(2.3^x=10.3^{12}+2^3.3^{12}\)
\(\Rightarrow\)\(2.3^x=3^{12}\left(10+8\right)\)
\(\Rightarrow\)\(2.3^x=3^{12}.18=3^{12}.2.3.3=3^{14}.2\)
Vậy x = 14
1.tính c = \(\left(1\cdot2\cdot3\cdot4+2\cdot3\cdot4\cdot5+...+18\cdot19\cdot20\cdot21\right)-5-10-15-...-200\)
2. tính d = \(\dfrac{1}{1\cdot2\cdot3}+\dfrac{1}{2\cdot3\cdot4}+...+\dfrac{1}{18\cdot19\cdot20}-\dfrac{3}{1\cdot2}-\dfrac{3}{2\cdot3}-...-\dfrac{3}{19\cdot20}\)
3.tìm x: \(2\left(x-3\right)-3\left(1-2x\right)=4+4\left(1-x\right)\)
4.tìm x: \(\dfrac{x-2}{2}-\dfrac{1+x}{3}=\dfrac{4-3x}{4}-1\)
giải nhanh giùm tớ nhé. ghi cả lời giả ra kìa
nho cac ban giup minh nhe
1.tim x thuoc N biet:
a)(2x+1)mu 3=125 b)(x-5)mu 4=(x-5)mu 6 c)2 mu x-15=17 d)(7x-11)mu 3=2 mu 5. 5mu 2+200
2.viet cac tich sau hoac thuong duoi dang luy thua cua mot so:
a)2 mu 5 . 8 mu 4 b)25.125 c)25 mu 5:25 mu 7
3.viet cac tich, thuong sau duoi dang luy thua:
a) 2 mu 10:8 mu 3 b)12 mu 7:6 mu 7 c)5 mu 8:25 mu 2
4.tinh gia tri cac bieu thuc sau:
a mu3 . a mu 9 (a mu 5)mu7 (a mu 6)mu 4. a mu 12 4.5 mu 2-2.3 mu 2
Rút gọn biểu thức sau:
B = \(3\cdot3^2\cdot3^3\cdot3^4\cdot...\cdot3^{100}\).
\(27^{x-1}=9^2\) tim x
giup mk
\(27< 3^{x-2}< 243\) tim x
giup mk
tim x thuoc N
a,\(\dfrac{1}{4}\cdot\dfrac{2}{6}\cdot\dfrac{3}{8}\cdot...\cdot\dfrac{31}{64}=2^x\)
b,\(\left(x-3\right)^3=125^2\)
c,\(7^{x+2}+2\cdot7^{x-1}=345\)
d,\(3^{x-5}-81=0\)
bai hoi dai cac ban giup mk
tìm x thuộc z biet (x ^3+7).(x^+12).(x^3+65).(x^3+130)
ai lam dung mk tk cho nhe
\(5^{x-1}< 1000\) tim x
giup mk
bài 2 viết mỗi tích, thương sau dưới dạng luỹ thừa
a) 4^10 x 2^30 b) 9^25 x 27^4 x 81^3 c) 25^50 x 125^5 d) 64^3 x 4^8 x 16^4
e)3^8:3^6 ; 2^10:8^3 ; 12^7 :6^7 ; 31^5 ; 81^3
f) 5^8 : 25^2 ; 4^9:64^2 ; 2^25 : 32^4 ; 125^3 : 25^4