\(5^{x-1}< 1000\)
\(\Rightarrow5^{x-1}< 5^1< 5^2< 5^3< ,5^4< 1000\)
\(\Rightarrow\left[{}\begin{matrix}x-1=1\\x-1=2\\x-1=3\\x-1=4\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=2\\x=3\\x=4\\x=5\end{matrix}\right.\)
Vậy....
( mk ko chắc đúng hay sai nx 
)
\(27^{x-1}=9^2\) tim x
giup mk
\(5^{x-1}< 1000\) tim x
\(27< 3^{x-2}< 243\) tim x
giup mk
tim x thuoc N
a,\(\dfrac{1}{4}\cdot\dfrac{2}{6}\cdot\dfrac{3}{8}\cdot...\cdot\dfrac{31}{64}=2^x\)
b,\(\left(x-3\right)^3=125^2\)
c,\(7^{x+2}+2\cdot7^{x-1}=345\)
d,\(3^{x-5}-81=0\)
bai hoi dai cac ban giup mk
tim x
\(2\cdot3^x=10\cdot3^{12}+8\cdot27^4\)
mk dang can gap giup mk nhe 
Tim x \(\in\) N
a)\(^{3^{x-2}}\)
b)\(3.4^{x-2}\)=19.2
c)\(5^{x+1}+5^{x+2}\)=810
d)\(\left(x-1\right)^5-\left(x-1\right)^2=0\)
e)\(2^x-15=17\)
Cac ban oi cac ban lam giup minh voi mai minh phai nop bai roi
tim x
\(5^{x-1}-1=0\)
nho cac ban giup minh nhe
1.tim x thuoc N biet:
a)(2x+1)mu 3=125 b)(x-5)mu 4=(x-5)mu 6 c)2 mu x-15=17 d)(7x-11)mu 3=2 mu 5. 5mu 2+200
2.viet cac tich sau hoac thuong duoi dang luy thua cua mot so:
a)2 mu 5 . 8 mu 4 b)25.125 c)25 mu 5:25 mu 7
3.viet cac tich, thuong sau duoi dang luy thua:
a) 2 mu 10:8 mu 3 b)12 mu 7:6 mu 7 c)5 mu 8:25 mu 2
4.tinh gia tri cac bieu thuc sau:
a mu3 . a mu 9 (a mu 5)mu7 (a mu 6)mu 4. a mu 12 4.5 mu 2-2.3 mu 2
bài 1 :
a) 10^6*10^2:1000^3
b)625^2*57*3125:25
Bài 2:
a) (x-5)^5=(x-5)^10
