a)2x= 32
x = 32:2
x= 16
b) 9x-1=9
9x= 9+1
9x=10
x= \(\dfrac{10}{9}\)
\(2x=32\)
=>\(x=16\)
\(9x-1=9\)
=>\(9x=10\)
=>\(x=\dfrac{10}{9}\)
Vậy...
Tìm x :
2x = 32
x = 32 : 2
x = 16
Vậy x = 16
9x - 1 = 9
9x = 9 + 1
9x = 10
=> \(x\in\varnothing\)
9x-1=9
9x-1=91
x-1=1
x=2(thõa mãn x∈N)
vậy x=2