\(\left(x-2\right)^3-27^2=0\)
\(\Leftrightarrow\left(x-2\right)^3=27^2\)
\(\Leftrightarrow\left(x-2\right)^2=9^3\)
\(\Leftrightarrow x-2=9\)
\(\Leftrightarrow x=11\)
Vậy ...
\(\left(x-2\right)^3-27^2=0\)
\(\Leftrightarrow\left(x-2\right)^3=27^2\)
\(\Leftrightarrow\left(x-2\right)^2=9^3\)
\(\Leftrightarrow x-2=9\)
\(\Leftrightarrow x=11\)
Vậy ...
\(27< 3^{x-2}< 243\) tim x
giup mk
\(27^{x-1}=9^2\) tim x
giup mk
tim x thuoc N
a,\(\dfrac{1}{4}\cdot\dfrac{2}{6}\cdot\dfrac{3}{8}\cdot...\cdot\dfrac{31}{64}=2^x\)
b,\(\left(x-3\right)^3=125^2\)
c,\(7^{x+2}+2\cdot7^{x-1}=345\)
d,\(3^{x-5}-81=0\)
bai hoi dai cac ban giup mk
Tìm x
3 x ( x - 3 ) 3 - 27 x ( x - 3 ) = 0
Tim x \(\in\) N
a)\(^{3^{x-2}}\)
b)\(3.4^{x-2}\)=19.2
c)\(5^{x+1}+5^{x+2}\)=810
d)\(\left(x-1\right)^5-\left(x-1\right)^2=0\)
e)\(2^x-15=17\)
Cac ban oi cac ban lam giup minh voi mai minh phai nop bai roi
Tìm x
\(3\left(x+1\right)^3-27\left(x+1\right)=0\)
tìm x
( 2x - 1 ) 5 - 27 x ( 2x - 1 ) 2 = 0
ai giải giùm mk cái