\(-x-\dfrac{1}{3}=\dfrac{4}{9}\\ \Rightarrow-x=\dfrac{4}{9}+\dfrac{1}{3}\\ \Rightarrow-x=\dfrac{7}{9}\\ \Rightarrow x=-\dfrac{7}{9}\)
\(-x-\dfrac{1}{3}=\dfrac{4}{9}\Rightarrow x+\dfrac{1}{3}=-\dfrac{4}{9}\Rightarrow x=-\dfrac{4}{9}-\dfrac{1}{3}=-\dfrac{7}{9}\)
= \(\dfrac{1}{9}\)
nếu cần giải chj tiết bảo mình nha