(x-5)(3-2x)=0
=> x-5 = 0 hoặc 3-2x=0
=> x=5 hoặc x = 3/2
`(x-5)(3-2x)=0`
`=>` $\left[ \begin{array}{l}x-5=0\\3-2x=0\end{array} \right.$
`=>` $\left[ \begin{array}{l}x=5\\2x=3\end{array} \right.$
`=>` $\left[ \begin{array}{l}x=5\\x=\dfrac{3}{2}\end{array} \right.$
Vậy phương trình có tập nghiệm `S={5,3/2}`
(x - 5)(3 - 2x)=0
=> Nếu x - 5 = 0 => x = 5.
Nếu 3 - 2x = 0 => x = 3/2.
=> x = 5 hoặc x = 3/2
Ta có: \(\left(x-5\right)\left(3-2x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-5=0\\3-2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5\\2x=3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5\\x=\dfrac{3}{2}\end{matrix}\right.\)
Vậy: \(S=\left\{5;\dfrac{3}{2}\right\}\)
