=>x^3-12x^2+48x-64=x^3-x^2-16x+4x^2-4x-64
=>-12x^2+48x-64=3x^2-20x-64
=>-15x^2+68x=0
=>15x^2-68x=0
=>x=0 hoặc x=68/15
=>x^3-12x^2+48x-64=x^3-x^2-16x+4x^2-4x-64
=>-12x^2+48x-64=3x^2-20x-64
=>-15x^2+68x=0
=>15x^2-68x=0
=>x=0 hoặc x=68/15
=>x^3-12x^2+48x-64=x^3-x^2-16x+4x^2-4x-64
=>-12x^2+48x-64=3x^2-20x-64
=>-15x^2+68x=0
=>15x^2-68x=0
=>x=0 hoặc x=68/15
=>x^3-12x^2+48x-64=x^3-x^2-16x+4x^2-4x-64
=>-12x^2+48x-64=3x^2-20x-64
=>-15x^2+68x=0
=>15x^2-68x=0
=>x=0 hoặc x=68/15
\(\dfrac{3}{x-4}\)\(-\dfrac{4}{4+x}\)\(=\dfrac{3x-4}{x^2-16}\)
a,x^2+2x/(x+1)^2+3-x^2-2x/(x-1)^2+3=16/x^4+4x^2+16
b,x^2/x^2+2x+2+x^2/x^2-2x+2=5(x^2-5)/x^4+4+25/4
96/x^2-16+7+x/4-x=2x-1/x+4-3
2/x-1 +3/x-2 =3/x-3
1/x+1+5-x/x-2=3/x^2-x-2-1
D)5 + 76/x^2-16 = 2x-1/x+4 - 3x-1/4-x
Giải pt :
\(\dfrac{x+2}{x^2+2x+4}+\dfrac{x-2}{x^2-2x+4}=\dfrac{6}{x\left(x^4+4x^2+16\right)}\)
a) \(\frac{1}{x-4}-\frac{2+x}{x+4}=\frac{x\left(7-x\right)}{x^2-16}\)
b) \(\frac{1}{x-1}+\frac{2x^2-5}{x^3-1}=\frac{4}{x^2+x+1}\)
Giải pt:
a) \(\dfrac{x+1}{x^2+2x+4}-\dfrac{x-2}{x^2-2x+4}=\dfrac{6}{x(x^4+4x^2+16)}\)
b) \(\dfrac{4x^{2} + 10}{x^{2} + 5} - \dfrac{9}{x^{2} + 4} = \dfrac{8}{x^{2} + 3} + \dfrac{6}{x^{2} + 1}\)
Giải pt: \(\dfrac{3}{5x-1}+\dfrac{2}{3-5x}=\dfrac{4}{\left(1-5x\right)\left(x-3\right)}\)
\(\dfrac{5+96}{x^2-16}=\dfrac{2x—1}{x+4}-\dfrac{3x-1}{4-x}\)
a) 5-4x=3x-9
b) (x-4)(3x+9)=0
c) (x/(x+4))+(12/(x-4))=(4x+48)/(x*x-16)
d) 4-2x=7-x
e) (x+4)(8-4x)=0
f) (x/(x+5))+(11/(x-5))=(x+55)/(x*x-25)
g) ((3x+2)/2) - ((3x+1)/6)= (5/3) +2x
h) 2x-(3-5x)=4(x+3)
i) 3x -6+x=9-x
k) 2t-3+5t= 4t+12
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