Question

(x-3)^{4 _=16/81}

Answer 1

Ta có:

(x - 3)⁴ = \(\frac{16}{81}\)

=> (x - 3)⁴ = \(\left(\frac{2}{3}\right)^4\)

=> \(\left[\begin{matrix}x-3=\frac{2}{3}\\x-3=\frac{-2}{3}\end{matrix}\right.\)

=> \(\left[\begin{matrix}x=\frac{2}{3}+3\\x=\frac{-2}{3}+3\end{matrix}\right.\)

=> \(\left[\begin{matrix}x=\frac{11}{3}\\x=\frac{7}{3}\end{matrix}\right.\)

Vậy \(\left[\begin{matrix}x=\frac{11}{3}\\x=\frac{7}{3}\end{matrix}\right.\).