\(\left(x+\dfrac{1}{2}\right)^4=\dfrac{2^4}{3^4}\Leftrightarrow x+\dfrac{1}{2}=\dfrac{2}{3}\Leftrightarrow x=\dfrac{1}{3}\)
\(\left(x+\dfrac{1}{2}\right)^4=\dfrac{2^4}{3^4}\Leftrightarrow x+\dfrac{1}{2}=\dfrac{2}{3}\Leftrightarrow x=\dfrac{1}{3}\)
Tìm x
1) \(\left(\dfrac{1}{16}\right)^x=\left(\dfrac{1}{8}\right)^6\) 2) \(\left(\dfrac{1}{16}\right)^x=\left(\dfrac{1}{8}\right)^{36}\) 3) \(\left(\dfrac{1}{81}\right)^x=\left(\dfrac{1}{27}\right)^4\)
4) \(\left(\dfrac{4}{9}\right)^x=\left(\dfrac{8}{27}\right)^{10}\) 5) \(2^x=4^5.4^3\) help me !!!!
Tìm x :
a)\(\dfrac{49}{81}\)=\(\dfrac{7^x}{9}\) b)\(\dfrac{-64}{343}\)=(\(\dfrac{-4^x}{7}\))
c)\(\dfrac{9}{144}\)=\(\dfrac{3^x}{12}\) d)\(\dfrac{-1}{32}\)=(\(\dfrac{-1^x}{2}\))
Giúp với ạ bài khó quá . Em cảm ơn ạ !
Tìm x biết:
a) \(\dfrac{-32}{\left(-2\right)^x}=4\) f) \(\left(3x-1\right)^3=\dfrac{-8}{27}\)
b) \(\left(\dfrac{1}{2}\right)^{2x-1}=\dfrac{1}{8}\) g) \(\left(2x+3\right)^2=\dfrac{9}{121}\)
c) \(\dfrac{1}{9}.27^x=3^x\) h) \(5^x+5^{x+2}=650\)
d) \(9^x:3^3=\dfrac{1}{243}\) i) \(\left(x-7\right)^{x+1}-\left(x-7\right)=0\)
e) \(\dfrac{x7}{81}=27\) m) \(\left(\dfrac{-3}{4}\right)^{3x-1}=\dfrac{256}{81}\)
a) \(\sqrt{\dfrac{81}{16}}\)- \(\left(\dfrac{-3}{2}\right)^2\) + \(\left|-\dfrac{5}{6}\right|\)
b) \(\left|3-\dfrac{23}{9}\right|\) + \(\left(\dfrac{4}{3}\right)^3\) : \(\left(\dfrac{4}{3}\right)^3\)
Tìm x,y biết:
1) \(\dfrac{x}{5}=\dfrac{y}{7}\) và x+y = 48
2) \(\dfrac{x}{4}=\dfrac{y}{-7}\) và x-y=33
3) \(\dfrac{x}{y}=-\dfrac{2}{5}\) và x+y =12
4) \(\dfrac{x}{3}=\dfrac{y}{5}\) và 2x+4y=28
5) \(\dfrac{x}{y}=\dfrac{3}{16}\) và 3x-y=35
Tìm x
a)\(\left(x+5\right)^3\)=-64
b)\(\left(2x-3\right)^2\)=9
c)\(\dfrac{x}{\dfrac{4}{2}}\)=\(\dfrac{4}{\dfrac{x}{2}}\)
d)\(\dfrac{-32}{\left(-2\right)^n}\)=4
e)\(\dfrac{8}{2x}=4\)
g)\(\left(\dfrac{1}{2}\right)^{2x-1}=\dfrac{1}{8}\)
h)\(\left(\dfrac{1}{2}\right)^2.x=\left(\dfrac{1}{2}\right)^5\)
i) \(\left(\dfrac{-1}{3}\right)x=\dfrac{1}{81}\)
tìm x :
a) \(\dfrac{x+1}{7}+\dfrac{x+1}{8}=\dfrac{x+1}{9}+\dfrac{x+1}{10}\)
b) \(\dfrac{x+1}{12}+\dfrac{x^2}{11}=\dfrac{x+3}{10}+\dfrac{x+4}{9}\)
c) \(\dfrac{x-2}{x-1}=\dfrac{x+4}{x+7}\)
d)\(\dfrac{3x+2}{5x+7}=\dfrac{3x-1}{5x-3}\)
2 tìm x,y,z
a) \(\dfrac{x}{2}=\dfrac{y}{3},\dfrac{y}{4}=\dfrac{z}{5}vàx^2-y^2=-16\)
b)2x=3y,5x=7z và 3x-7y+5z=30
a) \((\dfrac{1}{3}-2x)^2+\dfrac{5}{4}=\dfrac{21}{16}\)
b) \(\dfrac{4-x}{3}=\dfrac{5}{2}\)
c) \(7\dfrac{1}{3}-\left|x-1\right|:2=\dfrac{5}{2}\)
a: (x-1) ( x+5) > 0
b: (x-1) ( x+5) < 0
c) \(\left(x-\dfrac{1}{2}\right)^2=\dfrac{1}{16}\)
d)\(\dfrac{3}{4}-\dfrac{1}{4}\left|x-\dfrac{1}{7}\right|=\dfrac{1}{4}\)
e) 8 ( x+1) - 2 ( 2x + 5 ) = 0
g) ( 6x-1) - ( x + 8 ) =0
h) \(\left|7x-\dfrac{1}{4}\right|=1\)
x) -2x-3=-x+7