Question

(x-3)² - 4(x-5) = (4-x) ²

Answer 1

(x-3)²-4x+20=(4-x)²

x²-6x+9-4x+20=16-8x+x²

-10x+29=16-8x

-10x+8x=16-29

-2x=-13

x=13/2

Answer 2

Ta có : \(\left(x-3\right)^2-4\left(x-5\right)=\left(4-x\right)^2\)

=> \(x^2-6x+9-4x+20=16-8x+x^2\)

=> \(x^2-6x+9-4x+20-16+8x-x^2=0\)

=> \(13-2x=0\)

=> \(x=\frac{13}{2}\)

Vậy phương trình trên có nghiệm là \(S=\left\{\frac{13}{2}\right\}\)

Answer 3

\(\left(x-3\right)^2-4\cdot\left(x-5\right)=\left(4-x\right)^2\)

\(\Leftrightarrow\left(x^2-6x+9\right)-\left(4x-20\right)-\left(16-8x+x^2\right)=0\)

\(\Leftrightarrow x^2-6x+9-4x+20-16+8x-x^2=0\)

\(\Leftrightarrow-2x+13=0\)

\(\Rightarrow x=\frac{13}{2}\)