Question

( x -1 ) ^x+2= ( x-1 ) ^x+6

^{giúp min 5 phút nữa có bài}

Answer 1

có 2 trường hợp:

+TH1:

x=2 => (2-1)²⁺²=(2-1)²⁺⁶= 1³=1⁷=1

=TH2:

x=1 => (1-1)¹⁺²=(1-1)¹⁺⁶=0³=0⁷=0

Answer 2

Taco:\(\left(x-1\right)^{x+2}=\left(x-1\right)^{x+6}=>\left(x-1\right)^{x+2}-\left(x-1\right)^{x+6}=0\)=>\(\left(x-1\right)^{x+2}.\left(1-\left(x-1\right)^4\right)=0\)

=>\(\left[{}\begin{matrix}\left(x-1\right)^2=0\\1-\left(x-1\right)^4=0\end{matrix}\right.=>\left[{}\begin{matrix}x-1=0\\\left(x-1\right)^4=1\end{matrix}\right.=>\left[{}\begin{matrix}x=1\\x-1=\pm1\end{matrix}\right.\)=>\(\left[{}\begin{matrix}x=1\\x=0\\x=2\end{matrix}\right.\)