Question

Viết phương trình phản ứng thực hiện dãy chuyển hoá sau đây:

1) NO2 <-- NO <-- NH3 <--> N2 --> NO

2) NH4NO2-->N2-->NH3 -->Fe(OH)3-->Fe(NO)3-->NO2-->HNO3-->NaNO3--> O2

Answer 1

1/

\(\left(1\right)4NH_3+5O_2\xrightarrow[pt]{t^0}4NO+6H_2O\)

\(\left(2\right)NO+\frac{1}{2}O_2\rightarrow NO_2\)

\(\left(3\right)4NH_3+3O_2\underrightarrow{t^0}2N_2+6H_2O\)

\(\left(4\right)N_2+O_2\rightarrow2NO\uparrow\)

2/

\(\left(1\right)2NH_4NO_3\underrightarrow{t^0}2N_2+O_2+4H_2O\)

\(\left(2\right)N_2+3H_2\underrightarrow{\leftarrow}2NH_3\)

\(\left(3\right)3NH_3+FeCl_3+3H_2O\rightarrow Fe\left(OH\right)_3+3NH_4Cl\)

\(\left(4\right)Fe\left(OH\right)_3+3HNO_3\rightarrow Fe\left(NO_3\right)_3+3H_2O\)

\(\left(5\right)4Fe\left(NO_3\right)_3\rightarrow2Fe_2O_3+12NO_2+3O_2\)

\(\left(6\right)2NO_2+\frac{1}{2}O_2+H_2O\rightarrow2HNO_3\)

\(\left(7\right)NaOH+HNO_3\rightarrow NaNO_3+H_2O\)

\(\left(8\right)2NaNO_3\rightarrow2NaNO_2+O_2\)