TÌM TRƯỚC KHI HỎI
a)Ta có: \(2015=2016-1;2017=2016+1\)
\(\Rightarrow A=2015\cdot2017=\left(2016-1\right)\left(2016+1\right)=2016^2-1< 2016^2=B\)
b)Ta có:
\(C=\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^{16}-1\right)\left(2^{16}+1\right)=2^{32}-1< 2^{32}=D\)
a)Ta có:A=2015.2017=(2016-1)(2016+1)=20162-1<B=20162
b)Ta có:C=(2+1)(22+1)(24+1)(28+1)(216+1)
=(2-1)(2+1)(22+1)(24+1)(28+1)(216+1)=(22-1)(22+1)(24+1)(28+1)(216+1)
=(24-1)(24+1)(28+1)(216+1)=(28-1)(28+1)(216+1)=(216-1)(216+1)=232-1
=>C<D=232
\(a,B=2016^2=\left(2017-1\right)^2=2017^2-2.2017+1=2017.\left(2017-2\right)+1=2017.2015+1>2017.2015\)Hay A<B
Câu trả lời:
A) A = 2015.2017 và B = \(2016^2\)
Ta có :
\(2016^2\) = 2016.2016 => 2016 .(2015+1)= 2016.2015 +2016
2015.2017 => 2015.(2016+1) = 2015.2016 +2015
Ta thấy 2016.2015 = 2015.2016 mà 2015 < 2016
=> \(2016^2\) > 2015.2017 hay nói cách khác B>A
Mik chỉ giải đc câu A thôi :(
a ,Bấm máy tính ta có : 
A=4064225
B=20162 =4064256
=>A<B
b , b tương tự
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Đùa tí thôi , chớ ném đá , gạch , xi măng ,... ha
