Question

Tính:\(\left(\dfrac{1}{2}+2x\right)^2\)

Answer 1

\(\left(\dfrac{1}{2}+2x\right)^2=\left(\dfrac{1}{2}\right)^2+2.\dfrac{1}{2}.2x+\left(2x\right)^2=\dfrac{1}{4}+2x+4x^2\)

Answer 2

(\(\dfrac{1}{2}\)+2x)² = (\(\dfrac{1}{2}\))²+2.\(\dfrac{1}{2}\).2x+(2x)² = \(\dfrac{1}{4}\)+2x+4x²