Question

tinh:3.(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)

Answer 1

\(3.\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)\)

=\(\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)\)

=\(\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)\)

=\(\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)\)

=\(\left(2^{16}-1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)\)

=\(\left(2^{32}-1\right)\left(2^{32}+1\right)\)

=\(2^{64}-1\)