\(\sqrt{5+2\sqrt{6}}-\sqrt{13-4\sqrt{3}}=\sqrt{3}+\sqrt{2}-\left(2\sqrt{3}-1\right)=1+\sqrt{2}-\sqrt{3}\)
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Bài 1: Căn bậc hai
Các câu hỏi tương tự
Bài 1:
1.\(\sqrt{2-\sqrt{3}}\)
2.\(\sqrt{3+\sqrt{5}}\)
3.\(\sqrt{21-6\sqrt{6}}\)
4.\(\sqrt{5+2\sqrt{6}}-\sqrt{5-2\sqrt{6}}\)
5.\(\left(2-\sqrt{3}\right)\sqrt{7+4\sqrt{3}}\)
6.\(\sqrt{13+4\sqrt{10}}+\sqrt{13-4\sqrt{10}}\)
Thực hiện phép tính:
a)\(\sqrt{13+30\sqrt{2+\sqrt{9+4\sqrt{2}}}}\)
b)\(\left(\sqrt{3}-\sqrt{2}\right)\sqrt{5+2\sqrt{6}}\)
c)\(\sqrt{5-\sqrt{13+4\sqrt{3}}}+\sqrt{3+\sqrt{13+4\sqrt{3}}}\)
d)\(\sqrt{1+\sqrt{3+\sqrt{13+4\sqrt{3}}}}+\sqrt{1-\sqrt{3-\sqrt{13-4\sqrt{3}}}}\)
Mọi người giải gấp giúp em với!!!!
Gỉai giúp mk vs
\(\sqrt{21-6\sqrt{6}}\)
\(\sqrt{14-6\sqrt{5}}+\sqrt{14+6\sqrt{5}}\)
\(\left(3-\sqrt{2}\right)\sqrt{7+4\sqrt{3}}\)
\(\sqrt{13+4\sqrt{10}}+\sqrt{13-4\sqrt{10}}\)
\(\sqrt{6}\left(\sqrt{26+15\sqrt{3}}+\sqrt{26-15\sqrt{3}}\right)\)
Tính:
A=\(\sqrt{\sqrt{5}-\sqrt{3-\sqrt{29-6\sqrt{20}}}}\)
B=\(\sqrt{6+2\sqrt{5-\sqrt{13+\sqrt{48}}}}\)
C=\(\sqrt{4+\sqrt{5\sqrt{3}+5\sqrt{48-10\sqrt{7+4\sqrt{3}}}}}\)
D=\(\sqrt{3+\sqrt{5}}-\sqrt{3-\sqrt{5}}-\sqrt{2}\)
Tính:
a) dfrac{sqrt{7}-5}{2}-dfrac{6-2sqrt{7}}{4}+dfrac{6}{sqrt{7}-2}-dfrac{5}{4+sqrt{7}}
b) dfrac{2}{sqrt{6}-2}+dfrac{2}{sqrt{6}+2}+dfrac{5}{sqrt{6}}
c) dfrac{1}{sqrt{3}}+dfrac{1}{3sqrt{2}}+dfrac{1}{sqrt{3}}sqrt{dfrac{5}{12}-dfrac{1}{sqrt{6}}}
d) dfrac{2sqrt{3-sqrt{3+sqrt{13+sqrt{48}}}}}{sqrt{6}-sqrt{2}}
Đọc tiếp
Tính:
a) \(\dfrac{\sqrt{7}-5}{2}-\dfrac{6-2\sqrt{7}}{4}+\dfrac{6}{\sqrt{7}-2}-\dfrac{5}{4+\sqrt{7}}\)
b) \(\dfrac{2}{\sqrt{6}-2}+\dfrac{2}{\sqrt{6}+2}+\dfrac{5}{\sqrt{6}}\)
c) \(\dfrac{1}{\sqrt{3}}+\dfrac{1}{3\sqrt{2}}+\dfrac{1}{\sqrt{3}}\sqrt{\dfrac{5}{12}-\dfrac{1}{\sqrt{6}}}\)
d) \(\dfrac{2\sqrt{3-\sqrt{3+\sqrt{13+\sqrt{48}}}}}{\sqrt{6}-\sqrt{2}}\)
a) \(\sqrt{13-4\sqrt{3}}+\sqrt{7-4\sqrt{3}}\)
b) \(\sqrt{6+2\sqrt{5}}+\sqrt{6-2\sqrt{5}}\)
c) \(\sqrt{4+2\sqrt{3}}-\sqrt{4-2\sqrt{3}}\)
d) \(\sqrt{7+4\sqrt{3}}+\sqrt{7-4\sqrt{3}}\)
e) \(\sqrt{9+4\sqrt{5}}\)
f) \(\sqrt{23+8\sqrt{7}}\)
Rút gọn:
a.\(\sqrt{21-6\sqrt6}+\sqrt{9+2\sqrt{18}}-2\sqrt{6+3\sqrt{3}}\)
b.\(\sqrt{4+\sqrt{15}}-\sqrt{7-3\sqrt{5}}\)
c.\(\sqrt{\dfrac{13}{4}+\sqrt{3}}\)\(-\sqrt{\dfrac{7}{4}-\sqrt{3}}\)
rút gọn các biểu thức sau:
a,\(\sqrt{\sqrt{5}-\sqrt{3-\sqrt{29-12\sqrt{5}}}}\)
b,\(\sqrt{6+2\sqrt{5}-\sqrt{29-12\sqrt{5}}}\)
c,\(\sqrt{2+\sqrt{5-\sqrt{13-\sqrt{48}}}}\)
d,\(\left(3-\sqrt{5}\right)\sqrt{3+\sqrt{5}}+\left(3+\sqrt{5}\right)\sqrt{3-\sqrt{5}}\)
Rút gọn các biểu thức sau: ko tính
13-2sqrt{42}
46+6sqrt{5}
sqrt{3-sqrt{5}}.left(sqrt{10}-sqrt{2}right)left(3+sqrt{5}right)
sqrt{6+2sqrt{2}.sqrt{3-sqrt{4+2sqrt{3}}}}
sqrt[]{5}-sqrt{3-sqrt{29-12sqrt{5}}}
frac{sqrt{sqrt{7}-sqrt{3}}-sqrt{sqrt{7}+sqrt{3}}}{sqrt{sqrt{7}-2}}
Đọc tiếp
Rút gọn các biểu thức sau: ko tính
\(13-2\sqrt{42}\)
\(46+6\sqrt{5}\)
\(\sqrt{3-\sqrt{5}}.\left(\sqrt{10}-\sqrt{2}\right)\left(3+\sqrt{5}\right)\)
\(\sqrt{6+2\sqrt{2}.\sqrt{3-\sqrt{4+2\sqrt{3}}}}\)
\(\sqrt[]{5}-\sqrt{3-\sqrt{29-12\sqrt{5}}}\)
\(\frac{\sqrt{\sqrt{7}-\sqrt{3}}-\sqrt{\sqrt{7}+\sqrt{3}}}{\sqrt{\sqrt{7}-2}}\)