Bài 1: Căn bậc hai
Các câu hỏi tương tự
rút gọn biểu thức
a, \(\dfrac{1}{\sqrt{7-\sqrt{24}+1}}-\dfrac{1}{\sqrt{7+\sqrt{24}+1}}\)
b,\(\sqrt{\dfrac{3+\sqrt{5}}{3-\sqrt{5}}}+\sqrt{\dfrac{3-\sqrt{5}}{3+\sqrt{5}}}\)
c,\(\dfrac{4+\sqrt{7}}{3\sqrt{2}+\sqrt{4}+\sqrt{7}}+\dfrac{4-\sqrt{7}}{3\sqrt{7}-\sqrt{4}-\sqrt{7}}\)
Tính:
a) dfrac{sqrt{7}-5}{2}-dfrac{6-2sqrt{7}}{4}+dfrac{6}{sqrt{7}-2}-dfrac{5}{4+sqrt{7}}
b) dfrac{2}{sqrt{6}-2}+dfrac{2}{sqrt{6}+2}+dfrac{5}{sqrt{6}}
c) dfrac{1}{sqrt{3}}+dfrac{1}{3sqrt{2}}+dfrac{1}{sqrt{3}}sqrt{dfrac{5}{12}-dfrac{1}{sqrt{6}}}
d) dfrac{2sqrt{3-sqrt{3+sqrt{13+sqrt{48}}}}}{sqrt{6}-sqrt{2}}
Đọc tiếp
Tính:
a) \(\dfrac{\sqrt{7}-5}{2}-\dfrac{6-2\sqrt{7}}{4}+\dfrac{6}{\sqrt{7}-2}-\dfrac{5}{4+\sqrt{7}}\)
b) \(\dfrac{2}{\sqrt{6}-2}+\dfrac{2}{\sqrt{6}+2}+\dfrac{5}{\sqrt{6}}\)
c) \(\dfrac{1}{\sqrt{3}}+\dfrac{1}{3\sqrt{2}}+\dfrac{1}{\sqrt{3}}\sqrt{\dfrac{5}{12}-\dfrac{1}{\sqrt{6}}}\)
d) \(\dfrac{2\sqrt{3-\sqrt{3+\sqrt{13+\sqrt{48}}}}}{\sqrt{6}-\sqrt{2}}\)
Thực hiện các phép tính sau:
a. \(\dfrac{5\sqrt{3}-3\sqrt{5}}{\sqrt{5}-\sqrt{3}}-\dfrac{6}{\sqrt{15}+3}\)
b. \(\left(\sqrt{10+2\sqrt{21}}-\sqrt{10-2\sqrt{21}}\right)-\dfrac{4}{\sqrt{3}+1}\)
c. \(\left(\sqrt{3}-\sqrt{2}\right)\left(\sqrt{18}+\sqrt{27}\right)\)
1.)\(\sqrt{11+4\sqrt{6}}\)
2.)\(\sqrt{7-4\sqrt{3}}-\sqrt{8+2\sqrt{15}}\)
3.)\(\sqrt{4-2\sqrt{3}}+\sqrt{7+4\sqrt{3}}\)
4.)\(\sqrt{2-\sqrt{3}}+\sqrt{2+\sqrt{3}}\)
5.)\(\sqrt{4a^2-12a+9}vớia\ge\dfrac{3}{2}\)
6.)\(\sqrt{a^2-6a+9}+\sqrt{9+64a^2-48a}với\dfrac{3}{8}< a< 3\)
Rút gọn căn bậc hai theo hằng đẳng thức:
a)left(4sqrt{2}+sqrt{30}right).left(sqrt{5}-sqrt{3}right)sqrt{4-sqrt{15}}
b)2.left(sqrt{10}-sqrt{2}right).left(4+sqrt{6-2sqrt{5}}right)
c)left(7+sqrt{14}right).sqrt{9-2sqrt{14}}
d)sqrt{dfrac{289+4sqrt{72}}{16}}
e) left(sqrt{21}+7right).sqrt{10-2sqrt{21}}
f)sqrt{2-sqrt{3}.left(sqrt{6}+sqrt{2}right)}
g) sqrt{2}sqrt{8+3sqrt{7}}
h) sqrt{11+6sqrt{2}}
Đọc tiếp
Rút gọn căn bậc hai theo hằng đẳng thức:
a)\(\left(4\sqrt{2}+\sqrt{30}\right).\left(\sqrt{5}-\sqrt{3}\right)\sqrt{4-\sqrt{15}}\)
b)\(2.\left(\sqrt{10}-\sqrt{2}\right).\left(4+\sqrt{6-2\sqrt{5}}\right)\)
c)\(\left(7+\sqrt{14}\right).\sqrt{9-2\sqrt{14}}\)
d)\(\sqrt{\dfrac{289+4\sqrt{72}}{16}}\)
e) \(\left(\sqrt{21}+7\right).\sqrt{10-2\sqrt{21}}\)
f)\(\sqrt{2-\sqrt{3}.\left(\sqrt{6}+\sqrt{2}\right)}\)
g) \(\sqrt{2}\sqrt{8+3\sqrt{7}}\)
h) \(\sqrt{11+6\sqrt{2}}\)
Thực hiện các phép tính:
a. \(\left(\sqrt{80}+\sqrt{20}\right):\sqrt{45}\)
b. \(\left(\sqrt{3}-\sqrt{2}\right)\left(\sqrt{18}+\sqrt{27}\right)\)
c. \(\dfrac{5\sqrt{3}-3\sqrt{5}}{\sqrt{5}-\sqrt{3}}-\dfrac{6}{\sqrt{15+3}}\)
d. \(\left(\sqrt{10+2\sqrt{21}}-\sqrt{10-2\sqrt{21}}\right)-\dfrac{4}{\sqrt{3}+1}\)
Asqrt{19-3sqrt{ }40}-sqrt{19+3sqrt{ }40}
Bsqrt{21-6sqrt{ }6} +sqrt{9+2sqrt{ }18} -2sqrt{6+3sqrt{ }3}
Csqrt{6+2sqrt{ }2sqrt{ }3-sqrt{ }4+2sqrt{ }3}
Dsqrt{4+sqrt{ }15}-sqrt{7-3sqrt{ }5}
Esqrt{2+sqrt{ }3}+sqrt{2-sqrt{ }3}
Fsqrt{12-3sqrt{ }7}-sqrt{12+3sqrt{ }7}
G(3sqrt{2}+sqrt{6}).sqrt{6-3sqrt{ }3}
Hsqrt{9-4sqrt{ }5}-sqrt{14-6sqrt{ }5}
Isqrt{9-4sqrt{ }2}-sqrt{13-4sqrt{ }3}
Đọc tiếp
A=\(\sqrt{19-3\sqrt{ }40}\)-\(\sqrt{19+3\sqrt{ }40}\)
B=\(\sqrt{21-6\sqrt{ }6}\) +\(\sqrt{9+2\sqrt{ }18}\) -2\(\sqrt{6+3\sqrt{ }3}\)
C=\(\sqrt{6+2\sqrt{ }2\sqrt{ }3-\sqrt{ }4+2\sqrt{ }3}\)
D=\(\sqrt{4+\sqrt{ }15}\)-\(\sqrt{7-3\sqrt{ }5}\)
E=\(\sqrt{2+\sqrt{ }3}\)+\(\sqrt{2-\sqrt{ }3}\)
F=\(\sqrt{12-3\sqrt{ }7}\)-\(\sqrt{12+3\sqrt{ }7}\)
G=(3\(\sqrt{2}\)+\(\sqrt{6}\)).\(\sqrt{6-3\sqrt{ }3}\)
H=\(\sqrt{9-4\sqrt{ }5}-\sqrt{14-6\sqrt{ }5}\)
I=\(\sqrt{9-4\sqrt{ }2}\)-\(\sqrt{13-4\sqrt{ }3}\)
1/Tính
Adfrac{sqrt{15-10sqrt{2}}+sqrt{13+4sqrt{10}}-sqrt{11+2sqrt{10}}}{2sqrt{3+2sqrt{2}}+sqrt{9-4sqrt{2}}+sqrt{12+8sqrt{2}}}
Bdfrac{2+sqrt{3}}{sqrt{2}+sqrt{2}+sqrt{3}}+dfrac{2-sqrt{3}}{sqrt{2}-sqrt{2}-sqrt{3}}
Cdfrac{sqrt{2-sqrt{3}}+sqrt{4-sqrt{15}}+sqrt{10}}{sqrt{23-3sqrt{5}}}
Ddfrac{sqrt{4+sqrt{3}}+sqrt{4-sqrt{3}}}{sqrt{4+sqrt{13}}}
2/So sánh
sqrt{2017^2-1}-sqrt{2016^2-1} và dfrac{2.1016}{sqrt{2017^2-1}+sqrt{2016^2-1}}
Đọc tiếp
1/Tính
A=\(\dfrac{\sqrt{15-10\sqrt{2}}+\sqrt{13+4\sqrt{10}}-\sqrt{11+2\sqrt{10}}}{2\sqrt{3+2\sqrt{2}}+\sqrt{9-4\sqrt{2}}+\sqrt{12+8\sqrt{2}}}\)
B=\(\dfrac{2+\sqrt{3}}{\sqrt{2}+\sqrt{2}+\sqrt{3}}+\dfrac{2-\sqrt{3}}{\sqrt{2}-\sqrt{2}-\sqrt{3}}\)
C=\(\dfrac{\sqrt{2-\sqrt{3}}+\sqrt{4-\sqrt{15}}+\sqrt{10}}{\sqrt{23-3\sqrt{5}}}\)
D=\(\dfrac{\sqrt{4+\sqrt{3}}+\sqrt{4-\sqrt{3}}}{\sqrt{4+\sqrt{13}}}\)
2/So sánh
\(\sqrt{2017^2-1}-\sqrt{2016^2-1}\) và \(\dfrac{2.1016}{\sqrt{2017^2-1}+\sqrt{2016^2-1}}\)
rút gọn các biểu thức:
a) dfrac{sqrt{15}-sqrt{6}}{sqrt{35}-sqrt{14}}
b) dfrac{sqrt{10}+sqrt{15}}{sqrt{8}+sqrt{12}}
c) dfrac{2sqrt{15}-2sqrt{10}+sqrt{6}-3}{2sqrt{5}-2sqrt{10}-sqrt{3}+sqrt{6}}
d) dfrac{sqrt{2}+sqrt{3}+sqrt{6}+sqrt{8}+sqrt{16}}{sqrt{2}+sqrt{3}+sqrt{4}}
e) dfrac{x+sqrt{xy}}{y+sqrt{xy}}
f) dfrac{sqrt{a}+asqrt{b}-sqrt{b}-bsqrt{a}}{ab-1}
giải giúp mjk vs m.n :]] arigatou 3
Đọc tiếp
rút gọn các biểu thức:
a) \(\dfrac{\sqrt{15}-\sqrt{6}}{\sqrt{35}-\sqrt{14}}\)
b) \(\dfrac{\sqrt{10}+\sqrt{15}}{\sqrt{8}+\sqrt{12}}\)
c) \(\dfrac{2\sqrt{15}-2\sqrt{10}+\sqrt{6}-3}{2\sqrt{5}-2\sqrt{10}-\sqrt{3}+\sqrt{6}}\)
d) \(\dfrac{\sqrt{2}+\sqrt{3}+\sqrt{6}+\sqrt{8}+\sqrt{16}}{\sqrt{2}+\sqrt{3}+\sqrt{4}}\)
e) \(\dfrac{x+\sqrt{xy}}{y+\sqrt{xy}}\)
f) \(\dfrac{\sqrt{a}+a\sqrt{b}-\sqrt{b}-b\sqrt{a}}{ab-1}\)
giải giúp mjk vs m.n :]] arigatou <3