a: \(=x-2x^2+5-10x\)
\(=-2x^2-9x+5\)
\(=-2\left(x^2+\dfrac{9}{2}x-\dfrac{5}{2}\right)\)
\(=-2\left(x^2+2\cdot x\cdot\dfrac{9}{4}+\dfrac{81}{16}-\dfrac{121}{16}\right)\)
\(=-2\left(x+\dfrac{9}{4}\right)^2+\dfrac{121}{8}< =\dfrac{121}{8}\)
Dấu '=' xảy ra khi x=-9/4
b: \(=x^2-4x+4+\dfrac{1}{2}=\left(x-2\right)^2+\dfrac{1}{2}>=\dfrac{1}{2}\)
Dấu =xảy ra khi x=2