Question

Tính giá trị của biểu thức

a/ \(\dfrac{6^2.6^3}{3^5}\)

b/ \(\dfrac{25^2.4^2}{5^5.\left(-2\right)^5}\)

c/ \(\dfrac{2^7.9^3}{8^2.3^6}\)

d/ \(\dfrac{6^3+3.6^2+3^3}{-13}\)

Answer 1

a)\(\dfrac{6^2.6^3}{3^5}=\dfrac{2^2.3^2.2^3.3^3}{3^5}=2^5=32\)

b)\(\dfrac{25^2.4^2}{5^5\left(-2\right)^5}=\dfrac{5^2.5^2.2^2.2^2}{5^5.\left(-2\right)^5}=\dfrac{1}{-10}=-\dfrac{1}{10}\)

c)\(\dfrac{2^7.9^3}{8^2.3^6}=\dfrac{2^7.\left(3^2\right)^3}{\left(2^3\right)^2.3^6}=\dfrac{2^7.3^6}{2^6.3^6}=2\)

d)\(\dfrac{6^3+3.6^2+3^3}{-13}=\dfrac{2^3.3^3+3.2^2.3^2+3^3}{-13}=\dfrac{3^3\left(2^3+2^2+1\right)}{-13}\)

\(=\dfrac{3^3.13}{-13}=-3^3=-27\)