a.=\(\dfrac{4^3.9^3.5^44^4.18^2}{4^5.9^5.5^5}\)=\(\dfrac{4^4.9^2.2^2}{4^2.9^2.5}\)=\(\dfrac{4^2.2^2}{5}\)=\(\dfrac{64}{5}\)
Bài 2:
a) (2x+1)3 = 27
(2x+1)3 = 33
=> 2x+1 = 3
=> 2x = 2
=> x = 1
b,\(=\dfrac{4^8.4.3^6+4^8.4^4}{4^4.4^4.4.25}\)=\(\dfrac{4^8\left(4.3^6+4^4\right)}{4^9.25}\)=\(\dfrac{4.3^6+4^4}{4.25}\)=\(\dfrac{4\left(3^6+4^3\right)}{4.25}\)=\(\dfrac{3^6+4^3}{25}\)=\(\dfrac{793}{25}\)
b,3^2x+1.11=297
\(\Rightarrow\)3^2x+1=297:11=27
\(\Rightarrow\)3^2x+1=3^3
\(\Rightarrow\)2x+1=3
\(\Rightarrow\)2x=3-1=2
\(\Rightarrow\)x=2:2=1
c,(7x-11)^3=1000
\(\Rightarrow\)(7x-11)^3=10^3
\(\Rightarrow\)7x-11=10
\(\Rightarrow\)7x=10+11=21
\(\Rightarrow\)x=21:7=3
d,(x-5)^4=(x-5)^6
\(\Rightarrow\)(x-5)^6-(x-5)^4=0
\(\Rightarrow\)(x-5)^4.\([\)(x-5)^2-1\(]\)=0
\(\Rightarrow\)\(\left[{}\begin{matrix}\left(x-5\right)^4=0\\\left(x-5\right)^2-1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=5\\\left(x-5\right)^2=1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=5\\x=6\end{matrix}\right.\)
a, \(\dfrac{45^3.20^4.18^2}{180^5}\)
= \(\dfrac{5^3.9^3.4^4.5^4.9^2.2^2}{5^5.9^4.4^5}\)
= \(\dfrac{5^7.9^5.4^4.4}{5^5.9^5.4^4}\)
= \(\dfrac{5^7.9^5.4^5}{5^5.9^5.4^5}\)
= \(5^2=25\)