Question

Tính B=\(\sqrt{4+2\sqrt{3}}-\sqrt{4-2\sqrt{3}}\)

C=\(\sqrt{94-42\sqrt{5}}-\sqrt{94+42\sqrt{5}}\)

D=\(\left(4+\sqrt{15}\right)\left(\sqrt{10}-\sqrt{6}\right)\sqrt{4-\sqrt{15}}\)

E=\(\sqrt{6+\sqrt{24}+\sqrt{12}+\sqrt{8}}-\sqrt{3}-\sqrt{2}-15\)

F=\(\sqrt{5}-\sqrt{3-\sqrt{29-12\sqrt{5}}}\)

Answer 1

Mk làm đc có 3 câu thôi.

Answer 2

D = (4\(\sqrt{10}\) - 4\(\sqrt{6}\) + 5\(\sqrt{6}\) - 3\(\sqrt{10}\) )\(\sqrt{4-\sqrt{15}}\)

D = (\(\sqrt{10}\) + \(\sqrt{6}\) )\(\sqrt{4-\sqrt{15}}\)

D = \(\sqrt{\left(4-\sqrt{15}\right)10}\) + \(\sqrt{\left(4-\sqrt{15}\right)6}\)

D = \(\sqrt{40-10\sqrt{15}}\) + \(\sqrt{24-6\sqrt{15}}\)

D = \(\sqrt{\left(\sqrt{15}\right)^2-2.5.\sqrt{5}+5^2}\) + \(\sqrt{\left(\sqrt{15}\right)^2-2.3.\sqrt{15}+3^2}\)

D = \(\sqrt{\left(\sqrt{15}-5\right)^2}\) + \(\sqrt{\left(\sqrt{15}-3\right)^2}\)

D = 5 - \(\sqrt{15}\) + \(\sqrt{15}\) - 3 = 2

Answer 3

F=\(\sqrt{5}-\sqrt{3-\sqrt{29-12\sqrt{5}}}\)

=\(\sqrt{5}-\sqrt{3-\sqrt{\left(2\sqrt{5}-3\right)^2}}\)

=\(\sqrt{5}-\sqrt{3-2\sqrt{5+3}}\)

=\(\sqrt{5}-\sqrt{6-2\sqrt{5}}\)

=\(\sqrt{5}-\sqrt{\left(\sqrt{5}-1\right)^2}\)

=\(\sqrt{5}-\sqrt{5}+1\)

=1