`a) x(x+1)+4(x+1)=0`
`<=> (x+4)(x+1) =0`
`<=> [(x+4=0),(x+1=0):}`
`<=> [(x=-4),(x=-1):}`
Vậy `S={-4;-1}`
`b) x^2 -x =0`
`<=> x(x-1) =0`
`<=> [(x=0),(x=1):}`
Vậy `S={0;1}`
`c) 3x(x-3)-x+3=0`
`<=> 3x(x-3) - (x-3) =0`
`<=> (3x-1)(x-3) =0`
`<=> [(3x=1),(x-3=0):}`
`<=> [(x=1/3),(x=3):}`
Vậy `S={1/3;3}`