Question

a)2(x-4)^2-4x(4-x)=0
b)4x^2-8x=0
c)3x^2+6x=0
d)8x^2+4x^3=0

Answer 1

đầu bài là tìm x ạ

Answer 2

Answer 3

\(a,< =>2\left(x-4\right)^2+4x\left(x-4\right)=0< =>\left(x-4\right)\left(2x-8+4x\right)=0\)\(< =>\left(x-4\right)\left(6x-8\right)=0< =>\left[{}\begin{matrix}x=4\\x=\dfrac{4}{3}\end{matrix}\right.\)

b,\(< =>4x\left(x-2\right)=0< =>\left[{}\begin{matrix}x=0\\x=2\end{matrix}\right.\)

c,\(< =>3x\left(x+2\right)=0< =>\left[{}\begin{matrix}x=0\\x=-2\end{matrix}\right.\)

d,\(< =>4x^2\left(2+x\right)=0< =>\left[{}\begin{matrix}x=0\\x=-2\end{matrix}\right.\)