=>2x(x-3)-x+3=0
=>(x-3)(2x-1)=0
=>x=3 hoặc x=1/2
2x2-6x-x=-3
2x2-7x+3=0
=>\(\left\{{}\begin{matrix}x=3\\x=0,5\end{matrix}\right.\)
\(2x\left(x-3\right)-x=-3\\ \Leftrightarrow2x^2-6x-x+3=0\\ \Leftrightarrow2x^2-7x+3=0\\ \Leftrightarrow\left[{}\begin{matrix}x_1=3\\x_2=\dfrac{1}{2}\end{matrix}\right.\)