Question

tìm x

x^2 + 4 = 4x

Answer 1

\(x^2+4=4x\)

\(\Leftrightarrow x^2-4x+4=0\)

\(\Leftrightarrow\left(x-2\right)^2=0\)

\(\Leftrightarrow x=2\)

Vậy x = 2

Answer 2

\(x^2+4=4x\)

\(\Rightarrow x^2+4-4x=0\)

\(\Rightarrow x^2+4-2x-2x=0\)

\(\Rightarrow x\left(x-2\right)-2\left(x-2\right)=0\)

\(\Rightarrow\left(x-2\right)^2=0\)

\(\Rightarrow x=2\)