Question

Tìm x

\(\dfrac{4}{5}x^2\left(\dfrac{x}{3}-\dfrac{1}{2}\right)-\left(\dfrac{1}{5}x-\dfrac{2}{3}\right)\left(\dfrac{4x^2}{3}+1\right)=\dfrac{22}{45}x^2\)

MÌNH CẦN GẤP GIÚP MÌNH NHA

Answer 1

\(\dfrac{4}{5}x^2\left(\dfrac{1}{3}x-\dfrac{1}{2}\right)-\left(\dfrac{1}{5}x-\dfrac{2}{3}\right)\left(\dfrac{4}{3}x^2+1\right)=\dfrac{22}{45}x^2\)

\(\Leftrightarrow\dfrac{4}{15}x^3-\dfrac{2}{5}x^2-\left(\dfrac{4}{15}x^3+\dfrac{1}{5}x-\dfrac{8}{9}x^2-\dfrac{2}{3}\right)=\dfrac{22}{45}x^2\)

\(\Leftrightarrow\dfrac{4}{15}x^3-\dfrac{2}{5}x^2-\dfrac{4}{15}x^3-\dfrac{1}{5}x+\dfrac{8}{9}x^2+\dfrac{2}{3}-\dfrac{22}{45}x^2=0\)

\(\Leftrightarrow-\dfrac{1}{5}x=-\dfrac{2}{3}\)

hay x=10/3