\(\dfrac{4x}{x-3}< 0\)
<=> \(\left[{}\begin{matrix}\left\{{}\begin{matrix}4x< 0\\x-3>0\end{matrix}\right.\\\left\{{}\begin{matrix}4x>0\\x-3< 0\end{matrix}\right.\end{matrix}\right.\)<=>\(\left[{}\begin{matrix}\left\{{}\begin{matrix}x< 0\\x>3\end{matrix}\right.\\\left\{{}\begin{matrix}x>0\\x< 3\end{matrix}\right.\end{matrix}\right.\)
<=> 0 < x < 3
Vậy 0 < x < 3 t/m
Trong mat phang chon 6 diem phan biet, trong do khong co 3 diem nao thang hang. voi 3 diem bat ki trong 6 diem do luon co 2 diem ma khoang cach nho hon 673. CMR trong 6 diem da cho luon tim duoc 3 diem la 3 dinh cua mot tam giac co chu vi nho hoc 2019
tim x y z biết
a,4x^2+9y^2+4x-24y+17=0
b,2x^2+2y^2+z^2+2xy-2xz-6y+9=0
c,x^2+2y+2xy+2x+6y+5=0
Cho:
Q=(\(\dfrac{2x-x^2}{2x^2+8}\)-\(\dfrac{2x^2}{x^3-2x^2+4x-8}\)).(\(\dfrac{2}{x^2}\)+\(\dfrac{1-x}{x}\))
a, Tim dieu kien xac dinh
b, rut on q
c, Tinh Q khi x=2017
d, Tim x thuoc Z de Q thuoc Z
GIUP MINH VOI CAN GAP LAM!!!
1) tim x
A) x2-25-(x+5)=0
B) ( 2x-1)2-(4x2-1)=0
C) x2(x2+4)-x2-4=0
bai 1
a = (3x / 2x + 4 ) + (x +3 /x ^ 2 - 4 )
a . tim x de gia tri phan thuc a duoc xac dinh
b. rut gon a
c. tinh gia trin cua a khi x bang -3
d . tim gia tri cua x de phan thuc co gia tri bang 2
Tìm x
a) x^3 - 16x = 0
b) x^4 - 2x^3 + 10x^2 - 20x = 0
c) (2x - 3 )^2 = (x+5)^2
d) x^2(x-1) - 4x^2 + 8x - 4 = 0
e) x^2 + 4x + 3 = 0
f) x^3 - x^2 = 4x^2 - 8x + 4
g) 2(x+3) - x^2 - 3x = 0
cho hai so thuc x,y thoa man x^2+y^2=1. tim gia tri nho nhat cua p=x^6+y^6
tim a de:
\(\left(x^3-ax^2+1\right):\left(x-1\right)\)
Tìm x
e) x^2 + 4x + 3 = 0
f) x^3 - x^2 = 4x^2 - 8x + 4
g) 2(x+3) - x^2 - 3x = 0
