e) x2 + 4x + 3 = 0
( x2 + 4x + 4 - 4) + 3 = 0
(x + 2)2 - 1 = 0
(x + 2)2 = 1
x + 2 = 1
x = -1
Vậy x = -1
Mk chỉ làm đc câu a thôi, bạn thông cảm cho mk nhé!!!
Tìm x
a) x^3 - 16x = 0
b) x^4 - 2x^3 + 10x^2 - 20x = 0
c) (2x - 3 )^2 = (x+5)^2
d) x^2(x-1) - 4x^2 + 8x - 4 = 0
e) x^2 + 4x + 3 = 0
f) x^3 - x^2 = 4x^2 - 8x + 4
g) 2(x+3) - x^2 - 3x = 0
Bài 1: Tìm m để hai phương trình sau tương đương
3mx - 1=5m-x và (2x-1)m=3x-1
Bài 2
a, (14 - 2x)2(3-x)(2x-4)=0
b, (x+3)(2x+3)=4x2-9
c, 8x2=4x
d, x2+4x-5=0
e, x2-5x-14=0
f, x2+3x+3=0
g, 7x2+2x+1=0
h, 3x3+19x2+4x-12=0
Câu 1. Giải các phườn trình sau:
a, 3x+6=0
b, 2x-10=0
c, 3x-7=11
d, 3x-9=0
e, 3x(2-x) =15(x-2)
f, (x+5)(x+4)=0
g, x(x+4)=0
h, (2x -4)(x-2)=0
i, (x+1/5)(2x-3)=0
k, x²-4x=0
m, 4x²-1=0
n, x²-6x+9=0
l, (3x-5)²-(x+4)²=0
o, 7x(x+2)-5(x+2)=0
p, 3x(2x-5)-4x+10=0
q, (2-2x)-x²+1=0
r, x(1-3x)=5(1-3x)
s, 2x-3/4+x+1/6=3
t, x-3/4-2x+1/3=x/6
u, x+1/13+x+2/12=x+3/11+x+4/10
v, 2x+1/15+2x+2/14=2x+3/13+2x+4/12
Giúp e nha mn. E cảm ơn trc ạ!
a) 2(x+3)–x(x+3)=0
b) x2(2x+3)–8x–12=0
c) (2x–7)2–(x–3)2=0
d) (5x2+3x–2)2=(4x2–3x–2)2
e) x2+5x=6
f) x3–x2–x+1=0
g) (x2+2x)2–2(x2+2x)=3
rút gọn biểu thức: (27^10-5.81^4.3^12+4.9^8.3^8):41.3^24
giải phương trình: 4x^2-9-(2x+3)(2x-1)=0
x^3+x^2-4x=4
x^2(x^2+4)-x^2-4=0
(3x-3)^2=(x+5)^2
(2x-3)^2==(x+5)^2
x^2(x-1)-(4x^2+8x-4)=0
Tìm x:
a) 2x (x-5) -(x2-10x +25)=0
b) x2 - 9 +3x(x+3) = 0
c) x3 - 16x = 0
d) (2x+3)(x-2) - (x2 -4x+4) = 0
e) 9x2 -(x2 -2x +1)=0
f)x3-4x2 -9x +36 = 0
g) 3x - 6 = (x-1).(x-2)
i) (x-2).(x+2) +(2x+1)2 =-5x.(x-3) =5
k) x2 -1 = (x-1).(2x+3)
l) (2x-1)2 +(x+3).(x-3) -5x(x-2)=6
tìm x biết
a) \(x^2-2x-3=0\)
b) \(2x^2+5x-3=0\)
c) \(x^4-27x=0\)
d) \(2x\left(x-3\right)-\left(3-x\right)=0\)
e)\(x^2-9=2\left(x+3\right)^2\)
f)\(4x^2-4x+1=\left(5-x\right)^2\)
g) \(4x^2-8x+4=2\left(1-x\right)\left(1+x\right)\)
Giải các phương trình sau bằng cách đặt ẩn phụ
a)\(x^3-x^2-\frac{8}{x^3-x^2}=2\)
b)\(\frac{x^2+x-5}{x}+\frac{3x}{x^2+x-5}+4=0\)
c)\(\frac{x^2-x}{x^2-x+1}-\frac{x^2-x+2}{x^2-x-2}=1\)
d)\(\frac{4x}{4x^2-8x+7}+\frac{3x}{4x^2-10x+7}=1\)
e)\(8\left(x^2+\frac{1}{x^2}\right)-34\left(x+\frac{1}{x}\right)+51=0\)
f)\(\left(y+1\right)^4+y\left(y^2+1\right)=0\)
1. 6x(x - 10) - 2x+20=0 6. 3x2 - 6x+3=0
2. 3x2(x - 3) + 3(3 - x)=0 7. 4x2 - 10x+2=0
3. x2 - 8x+16=2(x -4) 8. x2 - 12x -18=0
4. x2 - 16 + 7x ( x+4)=0 9. 3x2 - 10x+3=0
5. x2 - 13x - 14=0 10. 5x2 - 10x+10=0
