\(x^{2016}=x^{2017}\)
\(\Rightarrow x^{2016}-x^{2017}=0\)
\(\Rightarrow x^{2016}.\left(1-x\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x^{2016}=0\\1-x=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)
Vậy........
Chúc bạn học tốt!!!
\(x^{2016}=x^{2017}\)
\(\Leftrightarrow0=x^{2017}-x^{2016}\)
\(\Leftrightarrow0=x^{2016}\left(x-1\right)\)
\(\Leftrightarrow\left[{}\begin{matrix}x^{2016}=0\\x-1=0\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)\(\left(TM\right)\)
Vậy \(x\in\left\{0;1\right\}\) là giá trị cần tìm
\(x^{2016}=x^{2017}\)
\(\Rightarrow x^{2017}-x^{2016}=0\)
\(x^{2016}\left(x-1\right)=0\)
\(x^{2016}=0\Rightarrow x=0\)
\(x-1=0\Rightarrow x=1\)
