\(\left(x-3\right)\left(x+3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\x+3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)
Vậy....
\(\left(x-3\right)\left(x+3\right)=0\)
\(\Leftrightarrow\left(x-3\right)=0\) hoặc \(\left(x+3\right)=0\)
\(\left[{}\begin{matrix}x-3=0\Rightarrow x=3\\x+3=0\Rightarrow x=-3\end{matrix}\right.\)
Vậy ....
(x-3)(x+3)=0
<=> \(\left[{}\begin{matrix}x-3=0\\x+3=0\end{matrix}\right.\)
<=> \(\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)
(x - 3)(x + 3) = 0
\(\Rightarrow\) x2 - 9 = 0
\(\Rightarrow\) x2 = 9
\(\Rightarrow\) x = \(\pm\) 3
cách của mik nhanh hơn nên cho mik 2 tik nhé ![]()
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