b: =>|x-1|=1-3x
\(\Leftrightarrow\left\{{}\begin{matrix}x< =\dfrac{1}{3}\\\left(1-3x-x+1\right)\left(1-3x+x-1\right)=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x< =\dfrac{1}{3}\\\left(-4x+2\right)\left(-2x\right)=0\end{matrix}\right.\Leftrightarrow x=0\)
c: =>2x-1=2x+3 hoặc 2x+3=1-2x
=>4x=-2
=>x=-1/2
d: =>x=0 và x+2=0
=>\(x\in\varnothing\)
e: \(\Leftrightarrow\left\{{}\begin{matrix}x>=0\\\left[x\left(x^2-\dfrac{5}{4}\right)-x\right]\left[x\left(x^2-\dfrac{5}{4}\right)+x\right]=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x>=0\\x\left(x^2-\dfrac{9}{4}\right)\cdot x\cdot\left(x^2-\dfrac{1}{4}\right)=0\end{matrix}\right.\Leftrightarrow x\in\left\{0;\dfrac{1}{2};\dfrac{3}{2}\right\}\)