Question

tìm x

a/ \(\dfrac{5^x}{125}\)= 25\(^4\) b/ \(\dfrac{3^x}{3}\)+ 3\(^{x-2}\) = 4

c/ (x + \(\dfrac{2006}{2007}\))\(^6\) =0 d/ (x-\(\dfrac{1}{5}\))\(^3\)= \(\dfrac{8}{125}\)

e/ 3\(^x\) + 3\(^{x-2}\)= 810 g/ 5\(^{x+2}\) +5\(^{x+1}\) +5\(^x\) = 19375

giúp mk nha các bn mk

Answer 1

a,

\(\dfrac{5^x}{125}=5^4\\ 5^x:5^3=5^4\\ 5^x=5^4\cdot5^3\\ 5^x=5^7\\ \Rightarrow x=7\)

b,

\(\dfrac{3^x}{3}+3^{x-2}=4\\ 3^{x-1}+3^{x-2}=3^1+3^0\\ \Rightarrow x=2\)

c,

\(\left(x+\dfrac{2006}{2007}\right)^6=0\\ \Rightarrow x+\dfrac{2006}{2007}=0\\ x=0-\dfrac{2006}{2007}\\ x=\dfrac{-2006}{2007}\)

d,

\(\left(x-\dfrac{1}{5}\right)^3=\dfrac{8}{125}\\ \left(x-\dfrac{1}{5}\right)^3=\left(\dfrac{2}{5}\right)^3\\ \Rightarrow x-\dfrac{1}{5}=\dfrac{2}{5}\\ x=\dfrac{2}{5}+\dfrac{1}{5}\\ x=\dfrac{3}{5}\)

e,

\(3^x+3^{x-2}=810\\ 3^x\left(1+3^2\right)=810\\ 3^x\cdot10=810\\ 3^x=810:10\\ 3^x=81\\ 3^x=3^4\\ \Rightarrow x=4\)

g,

\(5^{x+2}+5^{x+1}+5^x=19375\\ 5^x\left(5^2+5+1\right)=19375\\ 5^x\cdot31=19375\\ 5^x=19375:31\\ 5^x=625\\ 5^x=5^4\\ \Rightarrow x=4\)

Answer 2

sao đây đề dễ mà bên kia làm ko đc 1 bài haizzzzzzz