a,
b, (2x + 1)3 = -8
(2x + 1) = \(\sqrt[3]{-8}\)
2x + 1 = -2
2x = (-2) + (-1)
x = (-3) : 2
x = \(\dfrac{-3}{2}\) hay \(-1\dfrac{1}{2}\) hay -1,5
a: =>|x+2|=5/4:3/2=5/4*2/3=10/12=5/6
=>x+2=5/6 hoặc x+2=-5/6
=>x=-17/6 hoặc x=-7/6
b: =>2x+1=-2
=>2x=-3
=>x=-3/2