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\(\left(4x+3\right)^4=\left(4x+3\right)^2\)
\(\Rightarrow\left(4x+3\right)^4-\left(4x+3\right)^2=0\)
\(\Rightarrow\left(4x+3\right)^2\left[\left(4x+3\right)^2-1\right]=0\)
\(\Rightarrow\left(4x+3\right)^2\left(4x+3+1\right)\left(4x+3-1\right)=0\)
\(\Rightarrow\left(4x+3\right)^2\left(4x+4\right)\left(4x+2\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=-\dfrac{3}{4}\\x=-1\\x=-\dfrac{1}{2}\end{matrix}\right.\)
\(\left(4x+3\right)^4=\left(4x+3\right)^2\)
\(\Rightarrow\left[{}\begin{matrix}4x+3=-1\\4x+3=0\\4x+3=1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}4x=-4\\4x=-3\\4x=-2\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-1\\x=-0,75\\x=-0,5\end{matrix}\right.\)
(lí do chắc bn hiểu chứ)
Vậy \(x\in\left\{-1;\dfrac{-3}{4};\dfrac{-1}{2}\right\}\)
#nhanhgonnhedehieu
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