Question

Tìm x:

(2x+3)(3-2x)+(2x-1)²=2

Answer 1

\(\left(2x+3\right)\left(3-2x\right)+\left(2x-1\right)^2=2\)

\(\Leftrightarrow\left(3+2x\right)\left(3-2x\right)+\left(4x^2-4x+1\right)-2=0\)

\(\Leftrightarrow9-4x^2+4x^2-4x+1-2=0\)

\(\Leftrightarrow8-4x=0\)

\(\Leftrightarrow4x=8\)

\(\Leftrightarrow x=2\)

Vậy x=2

Answer 2

(2x+3)(3-2x)+(2x-1)²=2

=>(3+2x)(3-2x)+(2x-1)²=2

=>3²-4x²+4x²-4x+1=2

=>9-4x+1=2

=>-4x=-8 =>bạn tự tìm nốt nhé

Vậy...