a: \(\Leftrightarrow\left(\dfrac{19}{9}-\dfrac{15}{2135}\cdot\dfrac{4270}{9}\right):x=\dfrac{2}{3}\cdot\dfrac{21}{40}:\dfrac{1}{5}\)
=>-11/9:x=7/4
=>x=-11/9:7/4=-11/9*4/7=-44/63
b: =>(x-1)^2=81
=>x-1=9 hoặc x-1=-9
=>x=-8 hoặc x=10
Tìm x, biết:
a) \(\dfrac{27}{3^x}=3\)
b) \(9^{x-1}=\dfrac{1}{9}\)
Tìm GTNN của biểu thức:
\(\left|2021-x\right|+\dfrac{1}{\sqrt{\left(-2\right)^2}}.\left|4040-2x\right|\)
1. Cho xyz = 2019
Cm A = 2019/ 2019 +x + xy
+ 2019/ 2019 + z + xz + 2019/ 2019 + y + yz thuộc N
2. Tìm GTLN, GTNN ( nếu có )
A= 4x - 9 / |x|
3. So sánh
a) 3 × căn 2 và 7,(21)
b) 1/ căn 1 + căn 2 + 1/ căn 2 + căn 3 + ...... + 1/ căn 99 + căn 100 và 9
4. Tính S = x+ y + z biết 19/ x+ y + 19/ y + z + 19/ x + z = 14x/ y + z + 14y/ z + x + 14z/ x + y = 133/5
bài 6 : tìm x :
câu 9, \(3^x=9^{-6}.27^{-5}.81^8\)
câu 18, \(4^{x+3}-3.4^{x+1}=13.4^{11}\)
2. tìm x
a. \(\dfrac{x}{3}\)=\(\dfrac{-15}{6}\)
b. \(\dfrac{4}{9}\)+\(\dfrac{7}{3}\):x=\(\dfrac{1}{5}\)
c. \(\dfrac{x}{2}\)=\(\dfrac{-49}{14}\)
d. \(\dfrac{x}{27}\)-\(\dfrac{2}{9}\)=\(\dfrac{-1}{3}\)
e.(x+2,5):\(2\dfrac{1}{2}\)-1,5=\(-1\dfrac{1}{4}\)
1)tim x bit a)(1/2-1/3).6^x+6^x+2=6^15+6^18
b)3^x+3^x+2=2430
c)(2x-15)^5=(2x-15)^3
2) so saanh a)2^11 va 5^35
b)2^31 va 3^21
c)2^15 va 27^5.49^8 d)21^15 va 27^5.49^8
tìm x , biết :
a, \(\dfrac{37-x}{2x+5}=\dfrac{4}{9}\)
b, \(\dfrac{x-2}{x-1}=\dfrac{x+4}{x+7}\)
c, \(\dfrac{x+3}{25}=\dfrac{9}{x+3}\)
d, \(\dfrac{x}{\dfrac{-2}{3}}=\dfrac{5}{-x}\)
e, \(\dfrac{2x-5}{\dfrac{3}{2}}=\dfrac{\dfrac{-27}{8}}{5-2x}\)
f, \(\dfrac{\dfrac{5}{9}}{\left(3x-1\right)^2}=\dfrac{1-2x}{\dfrac{25}{3}}\)
Tìm x, biết rằng:
1) ( 2x + 1)3 = -0,001
2) ( 2x -3 )4 = ( 2x-3 )6
3) ( 2x+1 )5 = ( 2x+1)2010
4) \(\dfrac{8}{25}=\dfrac{2^x}{5^{x-1}}\)
5) 9x : 3x = 3
6) \(3^x+3^{x+3}=756\)
7) \(5^{x+1}+6.5^{x+1}=875\)
8) \(2^{x-1}.3^{y+1}=12^{x+9}\)
9) \(3^x=9^{y-1}\)
10) \(2^{x+1}.5^y=20^x\)
11) 15x : 3y = 75y
12) \(\dfrac{3}{5}:\dfrac{2x}{15}=\dfrac{1}{2}:\dfrac{4}{5}\)
13) \(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{4}\) và xy + yz + zx = 104
Tìm x:
a) 27x .9x = 927:81
b)\(\left(\dfrac{12}{25}\right)^x=\left(\dfrac{5}{3}\right)^{-2}-\left(\dfrac{-3}{5}\right)^4\)
