Question

Tìm số tự nhiên x biết

Answer 1

\(2^{x-2}-3.2^x=-88\)

\(\Rightarrow2^x.\frac{1}{4}-3.2^x=-88\)

\(\Rightarrow2^x.\left(\frac{1}{4}-3\right)=-88\)

\(\Rightarrow2^x.\frac{-11}{4}=-88\)

\(\Rightarrow2^x=-88:\frac{-11}{4}\)

\(\Rightarrow2^x=32\)

\(\Rightarrow2^x=2^5\)

\(\Rightarrow x=5\)

Vậy \(x=5\)

 

Answer 2

2^x-2 - 3.2^x = -88

2^x . 2^-2 - 3.2^x = -88

2^x . (2^-2 - 3) = -88

2^x . (1/4 - 3) = -88

2^x . (-11/4) = -88

2^x = -88 : (-11/4)

2^x = (-88).(4/-11)

2^x = 32

=> x = 5

Answer 3

\(2^{x-2}-3\cdot2^x=-88\)

\(2^x:2^2-3\cdot2^x=-88\)

\(2^x\cdot\left(\frac{1}{4}-3\right)=-88\)

\(2^x\cdot\left(-\frac{11}{4}\right)=-88\)

\(2^x=\left(-88\right):\left(-\frac{11}{4}\right)=32\)

\(2^x=2^5\)

\(\Rightarrow x=5\)

Answer 4

Ta có: 2^x-2 - 3.2^x=-88

2^x.2^-2-3.2^x=-88

2^x (1/4-3)=-88

2^x .(-11/4)=-88

2^x =-88:(-11/4)

2^x =32

=> x=5, vì 2⁵=32