Violympic toán 7
Các câu hỏi tương tự
cho x,y ti le thuan tim x biet x2=3,y1=-2,y2=\(\dfrac{3}{8}\) tim x2,y2biet y2-x2=-5,x1=-6,y1=4
Tim x;y
\(25-x^2=8\left(y+2009\right)^2\)
1)tim x bit a)(1/2-1/3).6^x+6^x+2=6^15+6^18
b)3^x+3^x+2=2430
c)(2x-15)^5=(2x-15)^3
2) so saanh a)2^11 va 5^35
b)2^31 va 3^21
c)2^15 va 27^5.49^8 d)21^15 va 27^5.49^8
Tim x, bt:\(\dfrac{1}{1.3}+\dfrac{1}{3.5}+\dfrac{1}{5.7}+...+\dfrac{1}{x\left(x+2\right)}=\dfrac{8}{17}\)
tim x
a)x-5/x-3 >0
b)x+8/x-9<0
c) (x+1)/2017 +(x+2)/2016 +(x+3)/2015 +(x+4)/2014 +4=0
Tính max
\(\dfrac{1}{\left(x-y\right)^2+\left(y-z\right)^2+\left(z-x\right)^2}\)
31 tháng 5 2018 lúc 14:55
Cho \(x;y;z>0\) thỏa: \(x^2+y^2+z^2=1\). Tìm max: \(P=x^2y^3z^4\)
Tim x,y biet x^2/9=y^2/16 va x^2+y^2=100
tim x biet 2.(x+1)-3.(x+2)=10