Ta có:\(A=\dfrac{12x-3}{x^2+5}\)
\(\Leftrightarrow A+3=\dfrac{12x-3}{x^2+5}+\dfrac{3x^2+15}{x^2+5}\)
\(\Leftrightarrow A+3=\dfrac{3x^2+12x+12}{x^2+5}\)
\(\Leftrightarrow A+3=\dfrac{3\left(x^2+4x+4\right)}{x^2+5}\)
\(\Leftrightarrow A+3=\dfrac{3\left(x+2\right)^2}{x^2+5}\ge0\)
\(\Leftrightarrow A\ge-3\)
\(\Rightarrow MINA=-3\Leftrightarrow x=-2\)