\(\left(x-1\right)\left(x-2\right)\left(x-5\right)\left(x-6\right)\)
\(=\left(x-1\right)\left(x-6\right)\left(x-2\right)\left(x-5\right)\)
\(=\left(x^2-6x-x+6\right)\left(x^2-5x-2x+10\right)\)
\(=\left(x^2-7x+6\right)\left(x^2-7x+10\right)\)
\(=\left(x^2-7x+8-2\right)\left(x^2-7x+8+2\right)\)
\(=\left(x^2-7x+8\right)^2-4\ge-4\)
Dấu "=" xảy ra khi:
\(x^2-7x+8=0\)