I zì:vv
a) Ta có: \(A=4x^2+4x+11=4x^2+4x+1=10=\left(2x+1\right)^2+10\ge10\forall x\)
Vậy MinA=10 khi \(x=-\dfrac{1}{2}\)
b) Ta có: \(B=5-8x-x^2=-\left(x^2+8x-5\right)=-\left(x^2+8x+16-21\right)\)
\(=-\left(x+4\right)^2+21\le21\forall x\)
Vậy MaxB=21 khi x=-4