\(-3sinx+4cosx=m-1\)
\(\Leftrightarrow5\left(-\frac{3}{5}sinx+\frac{4}{5}cosx\right)=m-1\)
\(\Leftrightarrow5.sin\left(x+\alpha\right)=m-1\) (với \(\alpha\) là góc sao cho \(cos\alpha=-\frac{3}{5}\) ; \(sin\alpha=\frac{4}{5}\))
Do \(-5\le sin\left(x+\alpha\right)\le5\)
\(\Rightarrow-5\le m-1\le5\Rightarrow-4\le m\le6\)