Với mọi x ta có :
\(\left|-\dfrac{2}{3}x-\dfrac{1}{2}\right|\ge0\)
\(\Leftrightarrow-\left|-\dfrac{2}{3}x-\dfrac{1}{2}\right|\le0\)
\(\Leftrightarrow-5,5-\left|\dfrac{-2}{3}x-\dfrac{1}{2}\right|\le-5,5\)
\(\Leftrightarrow A\le-5,5\)
Dấu "=" xảy ra
\(\Leftrightarrow\left|-\dfrac{2}{3}x-\dfrac{1}{2}\right|=0\Leftrightarrow x=-\dfrac{3}{4}\)
Vậy \(A_{Min}=-5,5\Leftrightarrow x=-\dfrac{3}{4}\)