+ Áp dụng bđt \(a+b\le\sqrt{2\left(a^2+b^2\right)}\) :
\(A=\sqrt{x-1}+\sqrt{y-2}\le\sqrt{2\left(x-1+y-2\right)}=\sqrt{2}\)
Dấu "=" \(\Leftrightarrow\left\{{}\begin{matrix}x-1=y-2\\x+y=4\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=\frac{3}{2}\\y=\frac{5}{2}\end{matrix}\right.\)