`N in Z`
`=>7 vdots x-1`
`=>x-1 in Ư(7)={+-1,+-7}`
`=>x in {0,2,8,-6}`
Để N là số nguyên thì \(7⋮x-1\)
\(\Leftrightarrow x-1\inƯ\left(7\right)\)
\(\Leftrightarrow x-1\in\left\{1;-1;7;-7\right\}\)
hay \(x\in\left\{2;0;8;-6\right\}\)
Vậy: \(x\in\left\{2;0;8;-6\right\}\)