Question

Tìm a ; b ; c biết :

\(\dfrac{a}{b+c-2016}+\dfrac{b}{a+c+2015}=\dfrac{c}{a+b+1}=\dfrac{a+b+c}{2016}\)

Answer 1

\(\dfrac{a+b+c}{b+c-2016+a+c+2015+a+b+1}=\dfrac{a+b+c}{2016}\)

Sau đó rút gọn đi rồi tính nha

STUDY WELL

Answer 2

Áp dụng tính chất dãy tỉ số bằng nhau, ta có:

\(\dfrac{a+b+c}{b+c-2016+a+c+2015+a+b+1}=\dfrac{a+b+c}{2016}\\ \Rightarrow\dfrac{a+b+c}{2a+2b+2c}=\dfrac{a+b+c}{2016}\\ \Rightarrow\dfrac{a+b+c}{2\left(a+b+c\right)}=\dfrac{a+b+c}{2016}\)